TMUA yotta mock paper 1

I’ve watched R2drew yt video but fro question 1, yotta says in the comments that u can solve it by looking at the coefficients of x^5 and x^6. Not sure how that works. Help pls

If you have a quadratic like
x^2 + 3x + 2 = 0
roots are -2 and -1 and 3 is their negaitve sum. So if you have a
(x-r1)(x-r2)(x-r3)(x-r4)(x-r5)(x-r6) = 0
what is the coeficient of x^5 and what would you do if the x^6 term is not unity?

Coefficient of x^5 is -15 and idk what u mean by unity for x^6?
How does that help with finding points of intersection with the line?

The intersection of the line does not affect the x^5 and x^6 terms, only the constant and the linear terms, so its basically the same as the basic root finding problem in terms of the sum of the roots. So the sum of the roots is not changed, even though the individual roots will be (as the constant and linear terms are altered). So youd get a 6th order polynomial like
pi x^6 - pi 15 x^5 + .... = 0
Dividing by pi to make the x^6 coefiicient unity means the x*5 coefficient is the (negated) sum of the points of intersection

I understand now. Ty