Original post by Lebkuchen
How is the velocity 0 at the maximum height visually?
s = ut - gt^2 / 2
then the gradient, ds/dt, is zero at the turning point of the parabola. Just plot in desmos or sketch it.
Heuristically, assuming positive is up, then a positive velocity must mean its moving upwards and a negative velocity is moving downwards. In the "middle" the velocity is zero so instantaneously its stationary at the max height because it stops moving upwards.
(edited 1 month ago)
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